Question
Two dice are thrown simultaneously. The probability
that the product of the two numbers on the two dice is an even number isSolution
Total number of outcome is 6*6 = 36. Now, according to the question we need the product of numbers on two dice to be even. We know “odd* even = even” as well as “even*even = even" But odd*odd = odd. So, the possibility of the odd number on the first dice is 3 (1, 3, 5) and similarly for 2nd dice. So, the number of outcomes when the product will be odd = 3*3 = 9 ways. So, required probability =36-9/36 = 27/36 = 3/4
18 45 90 235 450 1125 2250
...42, 85, 172, 343, 687, 1375
1, 4, 20, 126, 1026, 10170
79, 152, 231, 314, 405, 500
Find the wrong no in the given number series.
11, 18, 32, 60, 112, 228
Find the wrong number in the given number series.
21, 11, 12, 19, 41, 105
- Find the wrong number in the given number series.
154, 137, 114, 84, 46, 11 - Find the wrong number, in the given number series.
2, 5, 11, 23, 47, 97, 191 23, 36, 53, 69, 95, 124, 155
109 106 101 94 86 74
...
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