Question
Two dice are thrown simultaneously. The probability
that the product of the two numbers on the two dice is an even number isSolution
Total number of outcome is 6*6 = 36. Now, according to the question we need the product of numbers on two dice to be even. We know “odd* even = even” as well as “even*even = even" But odd*odd = odd. So, the possibility of the odd number on the first dice is 3 (1, 3, 5) and similarly for 2nd dice. So, the number of outcomes when the product will be odd = 3*3 = 9 ways. So, required probability =36-9/36 = 27/36 = 3/4
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