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Initial Men = 15. These 15 men can finish the work in 280 days. Total Work = 15 * 280 men-days days = 4200 men- days They work for 10 days. So, work done = 15*10 men-days. Now 15 more men were added, and they worked for 10 days= 30*10 men days Similarly for the next days 15*10+ 30*10+………….+ nth term = 15*280 10(15 + 30 + ..............nth term) = 15*280 So, this makes an AP. Sum= (n/2) *{2a + (n-1)d} Where n is the nth term, a= first element, d is the difference 15* 280= 10[(n/2) *{2*15 +(n-1)15}] 15*28 = (n/2)*(15+ 15n) 30*28 15n+ 15n2 n²+n = 56 So, n = 7, -8 (but n cannot be negative) So, n=7 It means 7*10 = 70 days So, work will be done in 70 days.
15(2/9) + 11(2/9) + 17(1/9) + 13(4/9) = ?
√361 ÷ (21/23) × 84 = ?
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
12(3/5) + 4(1/5) × 3(2/3) =?
If (7a + b) : (7a - b) = 7:3, then find the value of a:b?
?2 × 25 = 42 × 21 + 172
12% of 10% of 15% of 5000 + (12 x 15) = ?
525 ÷ 21 x 28 – 853 + 264 = ?