Question
A number consists of two digits such that the digit in
the ten’s place is less by 1 than the digit in the unit’s place. Three times the number added to 2/3 times the number obtained by reversing the digits equals 171. The sum of digits in the number is:Solution
Let the unit’s digit be x Ten’s digit = x – 1 Number = 10 (x – 1) + x = 10x – 10 + x = 11x – 10 New number obtained after reversing the digits = 10x + x – 1 = 11x – 1 According to the question 3(11x – 10) + (2/3) x (11x – 1) = 171 33x – 30 + 22x/3 – 2/3 = 171  99x – 90 + 22x – 2 = 171 x 3 121x – 92 = 513 121x – 92 = 513 x = 605/121 = 5 Number = 11x –10 = 11 × 5 – 10 = 45 Sum of digits = 4 + 5 = 9Â
{(1799.89 ÷ 8.18) ÷ 9.09 + 175.15} = 25.05% of ?
(22.93 × 11.92) + (17.78 ÷ 3.01) - (14.88 × 5.01) = ?
564.932 + 849.029 – 425.08 = 612.095 + ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
20% of 80 × 26% of 65 = ?
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
...(?)2 + 4.113 = 24.92 – 32.03Â
³√? `xx` 32.87 + 59.83 `xx` 28.7665 – 48.8745 `xx` 21.642 = 1085.344
13.99% of 399.99 ÷ 28.17 = ? ÷ 25.15
√92.10 + √256.30 + 60.78% of (420.90 + 19.36% of 140.25) = ?
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