Question
'A' purchased an article and sold it to 'B' at 10%
profit. 'B' marked it up by 26% above the price at which 'A' has purchased it and then sold it after giving a discount of Rs. 671.6. If 'B' suffered a loss of 12% in the transaction, then find the cost price of the article for 'A'.Solution
Let the cost price of the article for A be Rs. x Therefore, cost price of the article for B = Rs. 1.1x Marked price of the article = Rs. 1.26x Selling price of the article for B = 0.88 × 1.1x = Rs. 0.968x According to the question, 1.26x – 0.968x = 671.6 Or, x = 671.6/0.292 = 2300 Therefore, cost price of the article for A = Rs. 2300
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x2 + 6√7x - 315 = 0    Â
E...
I). p2 + 8p + 15 = 0
II). q2 + 9q + 20 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 30x + 221 = 0
Equation 2: y² - 28y + 189 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. p2 - 19p + 88 = 0  Â
II. q2Â - 48q + 576 = 0
I. 2x2 + 13x + 21 = 0
II. 3y2 + 34y + 63 = 0
I. 2y² - 11 y + 15 = 0
II. 2x² + 3x – 14 = 0
What will be the product of smaller roots of both equations.Â
(i) x² – 3x – 40 = 0
(ii) y² + 11y + 30 = 0
I. 99 x² + 31 x – 110 = 0
II. 6y² - 31y + 35 = 0
Relevant for Exams:
