Question
Average speed of ‘A’ during a 24-hour journey is 32
km/h. If he covered the first 120 km of his journey at a speed of 20 km/h, then find the speed at which ‘A’ travelled during the remaining journey.Solution
Total distance covered by ‘A’ = 24 × 32 = 768 km Time taken to cover 120 km = 120/20 = 6 hours Time taken to cover remaining distance = 24 – 6 = 18 hours So, required speed = {(768 – 120)/18} = 36 km/h
More ESIC Part B Questions
- Which letter and number cluster will replace the question mark (?) to complete the given series?
LT6, KU12, IW24, FZ48, ____ - Which letter-cluster will replace the question mark (?) in the following series?
RGV, UME, ?, AYW, DEF - A series is given with one term missing. Choose the correct alternatives from the given ones that will complete the series.
57, 59, 56, 61, 54, ___ - Which letter-cluster will replace the question mark (?) in the following series?
NPQR, OORQ, PNSP, ____, RLUN - Select the number from among the given options that can replace the question mark (?) in the following series.
17, 18, 22, 31, 47, ___
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