Question
A man invested Rs. 10,000 at simple interest of 'x%'
p.a. and received Rs. 20,000 after 2 years. If he had invested Rs. 25,000 at simple interest of 'x%' p.a. for 3 years, then find the interest earned by him from this investmentSolution
Total interest earned in 2 years = 20000 - 10000 = Rs. 10,000 ATQ; 10000 = (10000 × x × 2) ÷ 100 Or, x = 50 So, required interest earned = (25,000 × 50 × 3) ÷ 100 = Rs. 37500
More ESIC Part B Questions
115.98 + 109.01 + (√575 - 17) X 20.09 - 204.89 + 38.03 = ?
25.02% of 460.02+?% of 300.02=295.21
What approximate value will replace the question mark (?) in the following?
√40...
45.22 of 499.98% + 399.99 ÷ 20.18 = ?
118.95 – 24.10 + (91.90 ÷ 22.89 × 12.14) = ?
47.87% of 749.76 + 35.11% of 399.76 = √? + 23.15 × 20.87
32.052- 22.03 x 24.199 - 15.18 x 11.04 = ?
? = 49.97% of 38.09% of 1998.95
125.9% ÷ 9.05 x 99.98 = ? - 69.97 × √324.02 ÷ 5.98
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