Question
A man invested Rs. 10,000 at simple interest of 'x%'
p.a. and received Rs. 20,000 after 2 years. If he had invested Rs. 25,000 at simple interest of 'x%' p.a. for 3 years, then find the interest earned by him from this investmentSolution
Total interest earned in 2 years = 20000 - 10000 = Rs. 10,000 ATQ; 10000 = (10000 × x × 2) ÷ 100 Or, x = 50 So, required interest earned = (25,000 × 50 × 3) ÷ 100 = Rs. 37500
More ESIC Part B Questions
[(40)2 ÷ 32 × 4] ÷ 50 = ?
30% of 180 + 248 ÷ ? - √256 = 102
((67)32 × (67)-18 / ? = (67)⁸
- What will come in the place of question mark (?) in the given expression?
5555 ÷ 11 ÷ 5 = 100 +? What will come in the place of question mark (?) in the given expression?
642 - 362 = ? X √1225
115 ÷ 23 + 12 × 6 = ? + 16 - 35
2350 – 4830 + 9570 + 3350 – 1720 = ?
(-251 × 21 × -12) ÷ ? = 158.13
(288 ÷ 12 + 15 × 5 + 124) = ?
3.55 + 1.05 + 2.5 × 13 – 12% of 12.5 = ?
Relevant for Exams:
