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    Question

    Sum of squares of three consecutive numbers is 1877.

    Find the sum of first and third number.
    A 32 Correct Answer Incorrect Answer
    B 30 Correct Answer Incorrect Answer
    C 44 Correct Answer Incorrect Answer
    D 50 Correct Answer Incorrect Answer

    Solution

    Let the numbers be (x тАУ 1), x and (x + 1) => (x тАУ 1)2┬а+ x2┬а+ (x + 1)2┬а= 1877 => x2┬атАУ 2x + 1 + x2┬а+ x2┬а+ 2x + 1 = 1877 => 3x2┬а= 1877┬а- 2 => x2┬а= 1875/3 => x2┬а= 625 => x = 25 Required sum = (25 тАУ 1) + (25 + 1) = 50

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