Question
The time taken by ‘A’ to build a wall alone is 35%
more than the time taken by him to build it along with ‘B’. ‘B’ will take how much percent more time to build the same wall than the time taken by him to build it along with ‘A’?Solution
Let the work ‘A’ and ‘B’, can do in 1 day be ‘a’ units and ‘b’ units, respectively. Let they takes ‘p’ days to build the wall, together Therefore, Total work = (a + b) × p units …….. (1) According to the question, Time taken by ‘A’ to build the wall alone = 1.35p days Therefore, total work = 1.35p × a units….. (2) From equation (1) and (2), we get 20b/7 = a Therefore, total work to be done = (a + b) × p = 27bp/7 units Time taken by 'B' to build the wall = 27bp/7b = 27p/7 days Therefore, required percentage = (27p/7 – p)/p} × 100 = 285.71% more time
56. 23Â Â Â Â Â 45Â Â Â Â Â 89Â Â Â Â Â 177Â Â Â Â Â 363Â Â Â Â Â 705
...625, 5, 125, 25, 25, ? , 5
There are three series given below which are following with the same pattern.
Series I: 9, 10, 32, 163, 1145
Series II: 4, B, C, D, E
...5 14 56 220 1125 6786
...2,0, 9, 20, ‘?’, 714
7 29 ? 129 211 349
25Â Â Â Â Â Â Â Â Â Â 34Â Â Â Â Â Â Â Â Â Â 61Â Â Â Â Â Â Â Â Â Â 106Â Â Â Â Â Â Â Â 169Â Â Â Â Â Â Â Â ?
...9 10 6 15 -1 ?
...22   39    58    81   ?      141
The question below is based on the given series I. The series I satisfy a certain pattern, follow the same pattern in series II and answer the questions...
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