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Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 200’ km ATQ, (x/20) = {(x + 200)/30} Or, 30x = 20x + 4000 Or, 10x = 4000 So, x = 400 Total distance between station ‘A’ and station ‘B’ = (400 + 400 + 200) = 1000 km
A bought an article at 30% less of the marked price and sold it at 12% more than the marked price. Find the profit earned by him.
A bike is priced at Rs. 300 and sold after two successive discounts of 16% each. What is the final selling price?