Question
Two trains started from stations ‘A’ and ‘B’ at
same time and started travelling towards each other at speeds of 30 km/hr and 20 km/hr, respectively. At the time of their meeting, the faster train has travelled 200 km more than the slower train. Find the distance between the stations ‘A and ‘B’.Solution
Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 200’ km ATQ, (x/20) = {(x + 200)/30} Or, 30x = 20x + 4000 Or, 10x = 4000 So, x = 400 Total distance between station ‘A’ and station ‘B’ = (400 + 400 + 200) = 1000 km
(18.31)2 – (13.68)2 + (2344.20 + 82.32) ÷ ? = 229.90
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
24.01 X 24.99 - ?% of 599.96 = 14.92 X 8.12
20.11 × 6.98 + 21.03 × 6.12 – 37.95 + 92.9 × 5.02 =?
Direction: Solve the following expression and calculate the approximate value.
(5.78 + 3.12)² + 8.2² + 2 × 8.1 × (5.9 + 3.2)
...Find the approximate value of Question mark(?). No need to find the exact value.
(55.96 × 4.01) ÷ 7 + √(120.81) × 3 – 10% of 199.99 = ?<...
888.191 + 2.0001 X 7.961= ?
80.09 * √144.05+ ? * √224.87 = (2109.09 ÷ √1368.79) * 19.89
- 44.83% of 799.88 + (84.12 X 14.98 ÷ 62.87) = ?² + 55.65
The greatest number that will divide 398,436, and 542 leaving 7, 11, and 15 as remainders, respectively, is:
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