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Let total work = 60 units (LCM of 20 and 15) Efficiency of ‘A’ = (60/20) = 3 units/day Efficiency of ‘B’ = (60/15) = 4 units/day Combined efficiency of ‘A’, ‘B’ and ‘C’ = (60/5) = 12 units/day Efficiency of ‘C’ = 12 – (3 + 4) = 5 units/day Required time taken = (60/5) = 12 days
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