Question
Who virtually flagged off the 20 Broad Gauge (BG)
locomotives to Bangladesh in a handing over ceremony at Rail Bhavan New Delhi?Solution
To further strengthen bilateral relationship, 20 Broad Gauge (BG) locomotives were virtually flagged off to Bangladesh in a handing over ceremony at Rail Bhavan New Delhi, by Shri Ashwini Vaishnaw, Minister of Railways. In keeping with the requirements of Bangladesh Railway, the locomotives have been suitably modified by the Indian side. These locomotives will help handle the increasing volume of passenger and freight train operations in Bangladesh. As of now, five Bangladesh connectivity are operational, namely Geda- Darsana, Benapol- Petrapol, Singhabad- Rohanpur, Radhikapur- Birol and Haldibari-Chilahati. Work on two more cross border rail connectivities, Akhaura-Agartala and Mahihasan-Shahbazpur are progressing well and are likely to be completed and commissioned shortly. About Bangladesh Capital: Dhaka               Currency: Taka         Prime Minister: Sheikh Hasina
Statements: P # B, Q $ B, B @ J, J % F
Conclusions: Â Â Â Â Â I. F # BÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. F @ BÂ Â Â Â Â Â Â Â Â Â Â Â Â Â ...
Statements: J > K = L ≥ N > M > O ≥ P
Conclusions:
I. K ≥ O
II. J = N
III. P < NStatements: K ≥ L, N = R, L ≥ R, Q > C = K
Conclusions: I. R ≤ Q II. C ≥ N
In the question, relationship between some elements is shown in the statements (s). These statements are followed by two conclusions. Read the statemen...
Statements: B ≤ I; E = D; H > F; C ≤ H; I = D; A ≤ B; H < E
Conclusions:
(i) I > F
(ii) B ≤ H
(iii) A ≤ E
(iv) E > F
Statements: B > C, D > E, C = F, A ≥ F, D = A
Conclusion:
I. B ≥ E
II. E > B
Statement:Â C < P > T = E < R; G > R > A < D
Conclusions:
I. T < G
II. G ≥ P
III. T > A
Statements: T > V > Q > S; L > S > V ≥ O ≤ X < Y
Conclusions:
I. T > L
II. V ≥ Y
III. T > OÂ
In the question, assuming the given statements to be true, find which of the conclusion (s) among given two conclusions is /are definitely true and the...
Statement:  A = X ≥ W = B < C = O
Conclusions:
I. A ≥ B
II. W < O
III. X > O
IV. C > A
...
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