Question
Select the phrase(s) from the given three options which
can be used to form a single sentence from the two sentences given below, implying the same meaning as expressed in the statement sentences. The given options may or may not be starters. A. Secretion of insulin is usually tightly controlled and a healthy part of our body’s sugar-regulation processes. B. It can be significantly elevated in people with obesity-related pre-diabetes or diabetes due to insulin resistance. 1. Because secretion of insulin... 2. But it can be significantly... 3. Although secretion of insulin...Solution
The sentences are contradictory - A tells us that secretion of insulin is tightly controlled and a healthy part of our body’s sugar-regulation mechanism. B contradicts this by telling us how insulin is significantly elevated in people who have diabetes. 2 is correct as BUT is used to show contradiction - “Secretion of insulin is usually tightly controlled and a healthy part of our body’s sugar-regulation processes, but it can be significantly elevated in people with obesity-related pre-diabetes or diabetes due to insulin resistance.” 3 is correct as ALTHOUGH is used to show contradiction - “Although secretion of insulin is usually tightly controlled and a healthy part of our body’s sugar-regulation processes, it can be significantly elevated in people with obesity-related pre-diabetes or diabetes due to insulin resistance.”
Statements: M % C & G @ T $ D; W % M # P
Conclusions : I. D % C II. M % G ...
Statements: G > N > P = E ≥ H < L; M < E < B < C = Q > X; U > W > Y = Q > H
Conclusions:
I). U > P
II). Y > P
...Statements: A > B; C > D; E ≥ A; F = C; C < B
Conclusions:
(i) B > D (ii) A > F (iii) F < E
...Which of the following symbols should replace the question mark in the given statement in order to make conclusion 'B>Z' as well as 'C>X' definitely tr...
Statements: F % W, W © R, R @ M, M $ D
Conclusions:
I.D @ R II.M $ F�...
Statements: H > S ≥ F = B ≤ U≤ T; E ≤ B ≤ K
Conclusions:I. K > F II. K = F
Statements: B > K < Y, E > C ≥ O = Y
Conclusions:
I. C > B
II. E ≤ Y
III. E > K
IV. O ≥ K
...Statements: B > D = C ≥ E ≥ G, C = H ≤ I < F
Conclusions:
I. B > H
II. I ≥ G
III. F > DStatement: E < F ≤ G = H, I ≥ G ≤ J ≤ K
Conclusion: I. K > E II. H > K
...Statement: W>Y<X<Z=U>S; W<T ≥V
I. Y<T
II. X > V