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      Question

      Let Pr (X=2) = 1. Define µ2n = E(X-µ)^2n,

      µ = E(X). Then:
      A ┬╡2n = 2 Correct Answer Incorrect Answer
      B ┬╡2n = 0 Correct Answer Incorrect Answer
      C ┬╡2n > 0 Correct Answer Incorrect Answer
      D None of the above Correct Answer Incorrect Answer

      Solution

      Because Pr (X=2) = 1 is a sure event. E(X) = 2. Further, X - µ = 0 always. So, µ2n = 0 irrespective of what n is.

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