Question
Let Pr (X=2) = 1. Define µ2n = E(X-µ)^2n, µ = E(X).
Then:Solution
Because Pr (X=2) = 1 is a sure event. E(X) = 2. Further, X - µ = 0 always. So, µ2n = 0 irrespective of what n is.
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