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    Question

    Let Pr (X=2) = 1. Define µ2n = E(X-µ)^2n, µ = E(X).

    Then:
    A µ2n = 2 Correct Answer Incorrect Answer
    B µ2n = 0 Correct Answer Incorrect Answer
    C µ2n > 0 Correct Answer Incorrect Answer
    D None of the above Correct Answer Incorrect Answer
    E All of these are possible Correct Answer Incorrect Answer

    Solution

    Because Pr (X=2) = 1 is a sure event. E(X) = 2. Further, X - µ = 0 always. So, µ2n = 0 irrespective of what n is.

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