Question
How much time will Bus A take to cross Bus B (from the
moment they meet) running in opposite directions (towards each other)? I: The respective ratio of speeds of Bus A and Bus B is 9 : 5. The sum of the lengths of Bus A and Bus B is 1400 metre. II: Bus A can cross a signal pole in 15 seconds. It can cross 750 metre long stand in 20 seconds. In each of the following questions, a question is followed by two or three statement. Read all the statements and find that which statements are required to answer the question and answer accordingly.Solution
From statement I: Relative speed = 9x + 5x = 14x units Sum of Length of buses = 1400 metre Required time = 1400/(14 x) = no result From statement II: Let length of bus A = y Speed of Bus A = y/15 = (y + 750 )/20 ⇒ 20 y = 15 y + 11250 ⇒ 5 y = 11250 ⇒ y = 2,250 = length of bus A Now we can’t find answer by only one statement & if we use both, it will contradict each other because in 1st statement, sum of length of two buses is 1400 & in 2nd statement, length of bus A only is 2250 So we cant find answer by even using both statements.
√3598 × √(230 ) ÷ √102= ?
15% of 2400 + (√ 484 – √ 256) = ?
(13)2 - 3127 ÷ 59 = ? x 4
6269 + 0.25 × 444 + 0.8 × 200 = ? × 15
...(53 + 480 ÷ 4)% of 20 = ?% of 70
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
(15 × 225) ÷ (45 × 5) + 480 = ? + 25% of 1240
√ [? x 11 + (√ 1296)] = 16
11 × 25 + 12 × 15 + 14 × 20 + 15 = ?
Relevant for Exams:
