Question
What was the ratio between the total number of
female viewers of Aaj Tak in the year 2008 and 2009 and the total number of male viewers of the same channel in same years? Study the table carefully to answer the questions that follow: Total number of Male (M) and Female (F) viewers (in thousands) of four different TV News Channels.Solution
No. of female viewers of Aaj Tak in the year 2008 and 2009 = 46 + 65 = 111 No. of male viewers of Aaj Tak in the year 2008 and 2009 = 88 + 65 = 153 Reqd. ratio = 111:153= 37:51
l). p² - 29p + 204 = 0
ll). q² + 4q - 221 = 0
I. 2x2 – 5x - 12 = 0
II. y2 – 11y + 30 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 17x² - 78x + 61 = 0
Equation 2: 19y² - 89y + 70 ...
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 29x² - 137x + 108 = 0
Equation 2: 31y² - 146y + ...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 6x² - 24x + 18 = 0
Equation 2: 5y² - 20y + 15 = 0
I). 4p + 3q = 25
II). 5p + 2q = 26Â
I. 66x² - 49x + 9 = 0
II. 46y² - 37y - 30 = 0
I. 7x² + 52x + 21 = 0
II. 6y² + 7y - 24 = 0
Solve the equation:- x² − 9x + 20 = 0, What is the larger root?