Total work = Number of days×1 day’s work (efficiency) Total work = LCM (6, 12, 4) = 12 unit 1 day’s work of (A+B) = 12/6 = 2 unit 1 day’s work of (B + C) = 12/12 = 1 unit 1 day’s work of (A + B + C) = 12/4 = 3 unit Now, 1 day’s work of A = 3 – 1 = 2 1 day’s work of C = 3 – 2 = 1 1 day’s work of A and C = 2 + 1 = 3 A and C together can complete the job in = 12/3 = 4 days
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