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    Question

    Statements: All nice are tampered. All

    tampered are beaten. All mixed are beaten. Conclusions: I. No tampered is mixed. II. Some mixed are tampered. III. Some beaten are nice. IV. Some mixed are nice In each question below some statements followed by four conclusions numbered I, II, III and IV are given. You have to take the three given statements to be true even if they seem to be at variance with commonly known facts and then decide which of the given conclusions logically follows from the two given statements, disregarding commonly known facts.
    A Only either I or IV follows Correct Answer Incorrect Answer
    B Only either I or IV and II follow Correct Answer Incorrect Answer
    C Only III follows. Correct Answer Incorrect Answer
    D Only either I or II and III follow Correct Answer Incorrect Answer
    E None follows Correct Answer Incorrect Answer

    Solution

    All mixed are beaten(A) + All tampered are beaten ⇒ Conversion ⇒ Some beaten are tampered (I) ⇒ No conclusion. Hence neither conclusion I nor II follow but they will form a complementary pair. Hence either conclusion I or II follows. All nice are tampered(A) + All tampered are beaten ⇒ All nice are beaten (A) ⇒ Conversion ⇒ Some beaten are nice (I). Hence conclusion III follow. All nice are tampered(A) + All tampered are beaten ⇒ All nice are beaten (A) + All tampered are beaten ⇒ Conversion ⇒ Some beaten are tampered (I) ⇒ No conclusion. Hence conclusion IV does not follow. ALTERNATE SOLUTION:

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