We have, L sits third to the left of the one who has 22 pens, neither of them sits on the end of the row. Only one person sits between L and H. From the above condition, there are three possibilities. Case-1 Again we have, I sits second to the right of H. From the above condition, Case-2a gets eliminated. Case-1 Again we have, Only two persons are sitting between I and the one who has 15 pens. J sits second to the left of N, both have an odd number of pens. Case-1 Again we have, H has 10 pens less than M. L has two pens less than J and one more than K. J has one less than M. From the above condition, case1 shows the final arrangement. Case-1
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