We have, L sits third to the left of the one who has 22 pens, neither of them sits on the end of the row. Only one person sits between L and H. From the above condition, there are three possibilities. Case-1 Again we have, I sits second to the right of H. From the above condition, Case-2a gets eliminated. Case-1 Again we have, Only two persons are sitting between I and the one who has 15 pens. J sits second to the left of N, both have an odd number of pens. Case-1 Again we have, H has 10 pens less than M. L has two pens less than J and one more than K. J has one less than M. From the above condition, case1 shows the final arrangement. Case-1
118 × 6 + 13 + 83 = ?
What will come in the place of question mark (?) in the given expression?
(55 × 8 + 28) × 10 = ?
(13 X 11) + (19 X 3) = 400% of √?
135÷ 15 x 19 + 14807 = ? + √3249 - √9604
1240 ÷ ? = 242 + 123 – 514 × 4
(√7225 x √1225)/(√625) = ?
(512) (2/3) × √64 ÷ (512) (1/3) = (64) (?/2) ÷ (2)6
1/6+ 999*53/54 ×9 = ?
26 X √25 + 15 - 80% of 120 = ?2
540240 ÷ 24 ÷ 25 =?