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ATQ, Let the upstream and downstream speed of the boat be '4x' km/hr and '11x' km/hr, respectively. ATQ, 11x = (132/6) So, 'x' = 2 So, upstream speed of the boat = 4x = 4 × 2 = 8 km/hr Required distance = 8 × 9 = 72 km
25% of 300 + √(?) = 35% of 600 - 15% of 300
1053 ÷ 27 + 17 × 9 = ?
226 x 15 - 11 x 99 + (41)2 = ?
18(1/3) + 9(2/3) – 10(1/3) = 1(2/3) + ?
√(2670+ √(1141+ √(260- √(1251- √(637+ √1521) ) ) ) ) =?
1780 – 60 ÷ 4 x 80 = ?
√ [? x 11 + (√ 1296)] = 16
What will come in place of (?) in the given expression.
√625 + 12 × 5 = ?