A is 4 years older than N. Sum of number of biscuit of I and A's is 8 I and A's does not have even number of biscuit. Number of biscuit of N is three times of number of biscuit of A. I + A = 8 => 7 + 1= 8 and number of biscuit N is 3 C and N’s age difference and their difference of biscuit are same, in which their difference of ages will be the number of biscuit for K. C –N = 5(biscuit and age ) => 8 – 3 = 5 Number of biscuit of K is above 4. Number of biscuit of K is 5 Number of biscuit of V is below 3 Three persons were born between I and X. X was born after I. Sum of number of biscuit of G and V is 6. G + V = 6 => 4 + 2 = 6 and X’s biscuit is 6
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