Question
The age of Rajiv is twice the age of Suraj and half the
age of Mohan. Suraj is elder than Mehul. Who is the eldest?Solution
ATQ, Rajiv's Age Relations: Rajiv is twice the age of Suraj → Rajiv = 2 × Suraj Rajiv is half the age of Mohan → Mohan = 2 × Rajiv Express All Ages in Terms of Suraj's Age (S): Rajiv = 2S Mohan = 2 × (2S) = 4S Suraj = S Comparison: Mehul is younger than Suraj (not relevant for eldest). Mohan = 4S, which is the highest value. Hence, Mohan is the eldest
?% of (168 ÷ 8 × 20) = 126
20% of 1500 – 75% of 200 = 125% of ?
Find the value of 16 X [(8 - 5) of 12 ÷ 4].
√196 + (0.25 × 144) + 19 = ? + 72
22 * 6 + 45% of 90 + 65% of 180 = ?
52% of 400 + √(?) = 60% of 600 - 25% of 400
(25 × 12 + 30 × 8 – 22 × 10) = ?
What will come in the place of question mark (?) in the given expression?
(240% of 175 ÷ √16) X 6 + 80% of 400 = ?3 + 179 + 42
What will come in the place of question mark (?) in the given expression?
(144 × 16 ÷ 12) × 6 = ?
808 ÷ (128)1/7 + 482 = 4 × ? + 846
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