Question
The following question is based on the given words.
PLAN FORE RAMP RANG SAND If in each word, the fourth letter is changed to the next letter in the English alphabetical order, how many letter clusters thus formed will have two vowels?Solution
Let's apply the given transformation to each word: 1. PLAN → PLAO (P -> Q) 2. FORE → FORF (E -> F) 3. RAMP → RAMQ (P -> Q) 4. RANG → RANH (G -> H) 5. SAND → SANE (D -> E) Now, let's identify the clusters with two vowels: • PLAO: Contains two vowels (A, O) • FORF: Contains one vowel (O) • RAMQ: Contains one vowel (A) • RANH: Contains one vowel (A) • SANE: Contains two vowels (A, E) Out of the clusters formed, two of them have two vowels: PLAO and SANE. So, the answer is: 1. Two
?% of (168 ÷ 8 × 20) = 126
20% of 1500 – 75% of 200 = 125% of ?
Find the value of 16 X [(8 - 5) of 12 ÷ 4].
√196 + (0.25 × 144) + 19 = ? + 72
22 * 6 + 45% of 90 + 65% of 180 = ?
52% of 400 + √(?) = 60% of 600 - 25% of 400
(25 × 12 + 30 × 8 – 22 × 10) = ?
What will come in the place of question mark (?) in the given expression?
(240% of 175 ÷ √16) X 6 + 80% of 400 = ?3 + 179 + 42
What will come in the place of question mark (?) in the given expression?
(144 × 16 ÷ 12) × 6 = ?
808 ÷ (128)1/7 + 482 = 4 × ? + 846
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