Question
Which of the following letter cluster is the odd letter
cluster?Solution
In each letter cluster, the product of the positional value of each letter is '72'. Product of the positional value of 'HI' is (8 X 9) = 72 Product of the positional value of 'LF' is (12 X 6) = 72 Product of the positional value of 'DR' is (4 X 18) = 72 Product of the positional value of 'UE' is (21 X 5) = 105 So, 'UE' is the odd letter cluster.
32 × 3 (54 – 15) + 186 ÷ 3 ÷ 2 – (21)² = ?
17% of 250 + ? = 108
32 + 26 × (484 ÷ 44) + 450 ÷ 9 = ?
40 × 5 + 27) × 9 = ?
What will come in the place of question mark (?) in the given expression?
193...
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
What will come in the place of question mark (?) in the given expression?
√1296 + (2/3 of 45% of 480) = ?
- Determine the value of ‘p’ if p = √529 + √1444
120% of 250 + 110 + 135 ÷ 5 = ?
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