Question
How many numbers are there between 99 and 1000 such that
the digit 8 occupies the units place?Solution
These are of the form _ _ 8, where the last digit is 8.
So the units digit = 8.
Now, the hundreds digit can range from 1 to 9 (because it's a 3-digit number).
The tens digit can range from 0 to 9.
- Hundreds digit: 1 to 9 → 9 choices
- Tens digit: 0 to 9 → 10 choices
- Units digit: fixed as 8 → 1 choice
So, total number of such numbers = 9 x 10 x 1 = 90
(? × 3)2 - 85 = 115 × 5 + 69
25% of 160 × 18 = ? – 24
Solve.
15.73 +13.25 +16.73 – 28.71 = 5 ×?
What will come in the place of question mark (?) in the given expression?
√64 X 9 ÷ 3 + 12 X 3 = ? + 36(34.88% of 699.79) + 40.030 × 17.88 of 11.86 + 16.21 =? + (7.22)²
13 X √? + 256 ÷ 4 = 30% of 900 - 50
72 + 122 - 25% of 600 = ?
14% of 700 + 15% of 900 + 10% of 160 = ?
182 – 517 ÷ 11 - √361 = ?
If 1210 ÷ 22 + 1332 ÷ 37 - y + 54 × 3 = 980 ÷ 20 × 144 ÷ 48, then the value of y is:
