Question
A bus travels 40km north from stand. It turns right and travels 80km, then turns right and travels 100km. How far is the bus from the stand (minimum possible distance) and in which direction?
AC = BD = 80 Km DE = CD + CE => CE = 100 – 40 = 60 Km AE = √(CE²+AC²) AE = √(60²+80²) AE = √(3600+6400) = √10000 = 100 km Direction is South East.More Direction and Distance Questions
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