Question
Six persons D, E, F, G, H, and I stand in a queue
according to their weight. Who among the following is just heavier than D? Statement I: H is heavier than at least two persons. G is heavier than H. E is heavier than G. D is heavier than both F and I. D is heavier than H but lighter than G. Statement II: G is heavier than F, who is just heavier than I. E is heavier than H, D, and G. G is not the third heaviest. H is lighter than G. The question given below consists of two statements numbered I and II given below it. You have to decide whether the data provided in the statements are sufficient to answer the question. Read all the statement and answer the question.Solution
From statement I alone, H is heavier than at least two persons. G is heavier than H. E is heavier than G. D is heavier than both F and I. D is heavier than H but lighter than G. We get: E > G > D > H > F/I> I/F So, from statement I alone, we get G is just heavier than D. From statement II alone, we get: G is heavier than F, who is just heavier than I. E is heavier than H, D and G. G is not third heaviest. H is lighter than G. We get: Case 1: E > G > F > I > D/H > H/D Case 2: E > G > H/D > D/H > F > I Case 3: E > G > H/D > F > I > D/H So, from statement II alone, we cannot determine who is just heavier than D. Therefore, data given in statement I alone is sufficient to answer the question.
What will come in the place of question mark (?) in the given expression?
21 Γ 18 + ? β 19 Γ 15 = 25 Γ 24
- Find the value of the expression:
40 + 5 β 7 Γ [16 + 9 β 3 Γ (27 β 13)] What will come in place of (?) in the given expression.
12.5 + 7.75 - 3.6 = ?1299.999 Γ· 325.018 Γ 24.996 = ?
((9.77)0- γ(0.1)γ(-1))/(γ(6/24 )γ(-1)Β Γ(3/2)3+ γ((-2)/6)γ(-1) ) = ?
...(√121 + √196) × 7 =? × 5
2945 – 1508 + 3454 = ? + 2255
360 Γ· 9 + 15 % of 200 + ? * 10 = 45 * β25
30, 39, 66, ? , 174, 255