Question
Two positions of the same dice, having face numbered as
1, 5, 6, 7, 8, 9, are given. What will be the product of number opposite to both ‘7’ and ‘6’?Solution
According to the cube, ‘7’ must be opposite to ‘8’ and ‘1’ must be opposite to ‘9’. Only remaining number is ‘5’, which must be opposite to ‘6’. So, the product is 40 (8×5).
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