Question
If we increase all even digits by 1 and decrease all
odd digits by 2 in the number “8763432775” and then, arrange all the digits in descending order from the left end, then, what will be the sum of 2nd, 4th, 5th and 7th digits from the left end after the rearrangement?Solution
8 7 6 3 4 3 2 7 7 5 9 5 7 1 5 1 3 5 5 3 9 7 5 5 5 5 3 3 1 1 Sum of 2nd, 4th, 5th and 7th digits from the left end is = (7 + 5 + 5 + 3) = 20.
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