Question
If all the digits of the number ‘62943857’ are
rearranged in ascending order within the number from right to left, then what will be the product of the third digit from the right end and third digit from the left end of the number so formed?Solution
6 2 9 4 3 8 5 7
9 8 7 6 5 4 3 2
Required product = 7 x 4 = 28.
More Commonsense Reasoning Questions
(16.16 × 34.98) + 14.15% of 549.99 = ? + 124.34
? * 5.92 = (450.08 ÷ 9.99) % of 5180 - 921.12
(20.23% of 780.31) + ? + (29.87% of 89.87) = 283
(5.013 – 20.04) = ? + 9.98% of 6199.98
15.232 + 39.98% of 539.99 = ? × 6.99
(899.117 + 1.1121) X 72.731 = ? + 49.95 X 64.78 + 29.50
3.992 + (3.01 × 2.98) + ? = 225.03
? = 38.97² ÷ (3.99⁵ + 5.89 × 107.32) + 58.24% of (512.12 × 21.07)
5555.05 + 500.05 + 5000.005 + 5.005 =?
14, 27, 40, 53, 67, 79
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