Question
How many such pairs of digits are there in the given
number β84762395β each of which has as many digits between them in the number as in the Number series (From both backward and forward)?Solution
Forward β 46, 49, 69, 23, 25 Backward β 38, 67
If 83 Γ 24 = 5, 62 Γ 15 = 2, 45 Γ 33 = 3, then 96 Γ 42 = ?
Statements: L > J > W = Z < H < V β€ U; V > P > H β₯ C; I = V β€ E
Conclusions:
I. I > W
II. U > Z
III. I β€ E
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