Question
In a certain code language, βMβ is coded as
β29β and βIβ is coded as β88β then βSIPβ will be coded as ____ in the same code language.Solution
The letters are coded as: The digits of positional value of the letter in the English Alphabetical series is reversed and then subtracted by 2. (The positional value is taken in two digits). The positional value of βMβ is 13, so M is coded as (31 β 2) = 29. The positional value of βIβ is 09, so I is coded as (90 β 2) = 88. Similarly, βSIPβ will be coded as β89, 88, 59β.
β324 + β484 + 63 = ?2Β
`(450 -: ?)/(2.5 xx 1.2)` = 250
12 Γ 6 + 24 β 36 of 5 + 160 = ?
What will come in the place of question mark (?) in the given expression?
25% of 1280 + (41 Γ 4) = ?2Β
35 Γ 540 Γ· 18 of 15 β ? = 15Β
- Find the value of the expression:
25 + 9 β 8 Γ [10 + 14 β 2 Γ (33 β 18)] (? + 180 + 13 Γ 6) Γ· 20 + 3.5 Γ 512 (1/3) = 82
Find the simplified of the following expression:
33 × 5 - ?% of 250 = 62 - 6
What will come in the place of question mark (?) in the given expression?
(28/14) of 56 + ? = 920 Γ· 5