Question
Statements:Â Â Â Â Â Â Â A % O & Z % O; O # C & E; E @
P # D Conclusions :     I. C @ P               II. A % P               III. D @ O In the following questions, the symbols %, $, #, @ and & are used with the following meaning as illustrated below: ‘Y%Z’ means ‘Y is not smaller than Z’. ‘Y$Z’ means ‘Y is not greater than Z’. ‘Y#Z’ means ‘Y is neither greater than nor equal to Z’. ‘Y@Z’ means ‘Y is neither smaller than nor equal to Z’. ‘Y & Z’ means ‘ Y is neither greater than nor smaller than Z’. Now in each of the following questions assuming the given statements to be true, for conclusions I, II and III given below them is/are definitely true? Give answerSolution
Decoding: Statements: A ≥ O = Z ≥ O < C = E > P < D Conclusions :     I. C > P      II. A ≥ P              III. D > O A ≥ O = Z ≥ O < C = E > P < D         C > P. Hence, conclusion I follows. A ≥ O = Z ≥ O < C = E > P < D         No relationship can be established between A and P hence, conclusion II will not follow. A ≥ O = Z ≥ O < C = E > P < D         No relationship can be established between D and O hence, conclusion III will not follow.
Which of the following expressions will be true if the expression ‘J ≥ K > L ≥ M’ is definitely true?
Which of the following symbols should be placed in the blank spaces respectively (in the same order from left to right) to complete the given expression...
Statement: F ≥ G > I > E ≤ P, E = S ≥ PÂ
Conclusion: I. F ≥ PII. G > P
Statement: T > B = PÂ `>=` Â C ; BÂ `>=` Â J > F; OÂ `<=` Â JÂ `<=` Â CÂ Â Â Â
Conclusions:  I.  J < T    II. T > F
...Statement: C ≥ D > E ≥ H; I < E ≤ F < G
Conclusions: I. H > D II. G < H
...In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is /are definitely true and t...
Statements: Y > U = I; U > H; Z ≤ C ≤ E = Y
Conclusions:
I. U < C
II. E > I
III. I > H
Statements:
B > C = Z ≥ Q ≥ O; X < C ≤ D < O
Conclusions:
I. O > X
II. B > O
Statements:O < P,P < Q,Q < R
Conclusions: I. P < R II. P > Q
Statement: E ≤ F; E ≤ H; F = P; H < S
Conclusion:
I. S ≤ F
II. P ≥ S
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