Statements:  B & T, K ⋆ B, S ⋆ K
Conclusions:     a) K ⋆ T                b) S # T
given statements: B & T, K ⋆ B, S ⋆ K After converting: B < T, K ≥ B, S ≥ K After combining: S ≥ K ≥ B < T Conclusion a → K ⋆ T → K ≥ T The relation between K and T in the statement S ≥ K ≥ B < T : K ≥ T As there is no relation between K and T. So, it is not true. Conclusion b → S # T → S ≤ T The relation between S and T in the statement S ≥ K ≥ B < T : S ≤ T. As there is no relation between S and T. So, it is also not true.
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