Question
Statements: R © K, K * N, N $ J, J % H
Conclusions:     I.R $ N                  II.J @ K                               III.H @ N            IV.K $ H In the following questions, the symbols @, © , %, $ and * are used with the following meaning as illustrated below.  ‘P © Q’ means ‘P is not smaller than Q’.  ‘P * Q’ means ‘P is not greater than Q’. ‘P @ Q’ means ‘P is neither greater than nor equal to Q’. ‘P $ Q’ means ‘P is neither smaller than nor equal to Q’. ‘P % Q’ means ‘P is neither greater than nor smaller than Q’.Solution
given statements: R © K, K * N, N $ J, J % H After converting: R ≥ K, K ≤ N , N > J , J = H After combining: R ≥ K ≤ N > J = H Conclusion a → R $ N → R > N ( R ≥ K ≤ N ) No relationship can be established between R and N so, it is not true. Conclusion b → J @ K → J < K ( K ≤ N > J ) No relationship can be established between J and K so, it is not true. Conclusion c → H @ N → H < N (N > J = H ) , it is true. Conclusion d → K $ H → K > H ( K ≤ N > J = H), No relationship can be established between K and H so, it is not true.
In the following question the relationship between different elements is given in the statements followed by three conclusions I, II and III. Read the...
Statements: W ≤ T = R; T < U < S; X = W ≥ Y
Conclusions:
I. S > Y
II. W ≥ S
III. U ≥ Y
Statements:
A ≥ Z > B ≥ Y; C > B ≥ W
Conclusion:
I. A > W
II. C > Y
Statements: N & C, C # I, I @ L, L % Y
Conclusions: I.   C & Y                   II. L # N
...Statements: C > D = E ≥ G; F = G ≥ J < O
Conclusions:
I. D ≥ J
II. J < D
Statements: M > N < O, J < K < L, L = P > Q ≥ U = M
Conclusions:
I. L > N
II. Q < J
III. Q > OStatements: S < V = J ≤ G < K, P > L > C, K = A > P
Conclusions:
I. V > P
II. C < K
III. A > S
In the question, assuming the given statements to be true, find which of the conclusion (s) among given two conclusions is/are definitely true and then...
If the expressions G < L ≤ J > B, J ≤ A and G > H are true, which of the following conclusions will be definitely false?
Statements: A < B ≤ C ≤ D; A > E = G ≥ I; D ≤ H = J < F
Conclusions:
I. F > C
II. H > I
III. B < J
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