Statements:
E ≤ A > J ≥ L; Y > J < D
Conclusions:
I. D > L
II. A > L
Given: E ≤ A > J ≥ L; Y > J < D On combining: E ≤ A > J < D; J ≥ L, J < Y I. D > L - True (J < D; J ≥ L) II. A > L - True (A > J ≥ L) Hence, the conclusions I & II follows.
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