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    Question

    If it was Sunday on 5th January, 1986, what was the day of

    the week on 14th January, 1993?
    A Thursday Correct Answer Incorrect Answer
    B Saturday Correct Answer Incorrect Answer
    C Friday Correct Answer Incorrect Answer
    D Monday Correct Answer Incorrect Answer

    Solution

    On 5 th January, 1986, it was Sunday. 1986 was not a leap year.
    The number of odd days in a non-leap year is '1'.
    The number of odd days in a leap year is '2'.
    So, number of odd days from 5 th January, 1986 to 5 th January, 1993 = (1 + 1 + 2 + 1 + 1 + 1 + 2) days = 9 days
    The number of days from 5 th January, 1993 to 14 th January, 1993 = 9 days

    The days of the week repeat itself after 7 days, so, (18÷7) , we get 4 as remainder.
    So, number of odd days = 4
    As, it was it was Sunday on 5 th January, 1986, so, 4 th day after Sunday is Thursday.
    Therefore, on 14 th January, 1993, it was Thursday.

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