Question
Ujwal took a loan at 18% per annum simple interest for 2
years and repaid a total of Rs. 40,800. If he had instead taken the same loan at r % per annum compound interest, compounded annually for 2 years, he would have paid Rs. 2,400 more in interest. Find the value of r.Solution
Let principal = Rs. P
Given, P + (P * 18 * 2)/100 = 40800
=> P = 30000
S.I = 40800 - 30000 = Rs. 10800
C.I = 10800 + 2400 = Rs. 13200
Total amount at C.I = 30000 + 13200 = Rs. 43200
30000(1+r/100) 2 Â = 43200
=>(1+r/100) 2 Â = 144/100
=> 1 + r/100 = 12/10
=>r = 20
I. 104x² + 9x - 35 = 0
II. 72y² - 85y + 25 = 0
I. 2y2 - 37y + 143 = 0
II. 2x2 + 15x – 143 = 0
I. p2 - 19p + 88 = 0  Â
II. q2Â - 48q + 576 = 0
I. x2 + 13x + 42 = 0
II. y² + 13y + 40 = 0
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
I. 35x² - 46x – 16 = 0
II. 35y² - 116y + 96 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 34x + 288 = 0
Equation 2: y² - 29y + 210 = 0
I. 8/(21x) - 2/7 = 0
II. 16y² - 24y +9 = 0
I. 2x² - 7x + 3 = 0
II. 8y² - 14y + 5 = 0
Equation 1: x² + 16x + 63 = 0
Equation 2: y² + 10y + 21 = 0
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