Question
Ujwal took a loan at 18% per annum simple interest for 2
years and repaid a total of Rs. 40,800. If he had instead taken the same loan at r % per annum compound interest, compounded annually for 2 years, he would have paid Rs. 2,400 more in interest. Find the value of r.Solution
Let principal = Rs. P
Given, P + (P * 18 * 2)/100 = 40800
=> P = 30000
S.I = 40800 - 30000 = Rs. 10800
C.I = 10800 + 2400 = Rs. 13200
Total amount at C.I = 30000 + 13200 = Rs. 43200
30000(1+r/100) 2 = 43200
=>(1+r/100) 2 = 144/100
=> 1 + r/100 = 12/10
=>r = 20
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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