Question
Determine the sum of all two-digit numbers that, when
divided by both 6 and 8, leave a remainder of 4.Solution
LCM (6, 8) = 24So, smallest 2-digit number that leaves 4 as remainder when divided by both 6 and 8:= 24 + 4 = 28And, next numbers:(24 X 2) + 4 = 52(24 X 3) + 4 = 76So, required sum = 28 + 52 + 76 = 156
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