Question
An initial investment grows to four times its original
amount in 6 years under compound interest. How many years will it take for the investment to grow to 16 times its original amount under the same conditions?Solution
Let the amount invested be Rs. 'P' and rate of interest is 'R%' p.a.
Amount = Principal X [(1 + (R/100) ]time
So, 4P = P X [1 + (R/100) ]6
Or, [1 + (R/100) ]6Â = 4
On squaring both sides,
We get, [1 + (R/100) ]12Â = 16
Therefore, required time = 12 years
19.89% of 449.67 + 14.67% of 299.89 - 9.89% of 99.79 = ?
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
? = 200.14 + 27.98 × 16.05 − (10.03)² - 12.9...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
1299.999 ÷ 325.018 × 24.996 = ?
What approximate value should replace the question mark?
99.95 − √529 × 3 + 1439.80 ÷ 12.02 = ?
619.97 ÷ 20.01 X 124.99 ÷ 24.91 = ?
124% of 620.99 + 11.65% of 1279.23 = ?
What approximate value should replace the question mark?
9.96% of 1200.10 − 25% of 4800 = ? − 7000.20
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