Question
Find the wrong number in the given number series.
78, 66, 51, 39, 20, 12Solution
ATQ, 78 – 12 = 66 66 – 15 = 51 51 – 12 = 39 39 – 15 = 24 24 – 12 = 12 24 will come in the place of 20.
?% of 320 = 40% of 40 × 5
(2 ÷ 3) × (4 ÷ 12) × (? ÷ 10) × 45 × (1 ÷ 5) = (? ÷ 6) + (2 ÷ 5)
2(3/4) of 2880 + 54% of 7520 - ? = 302
(82 + 62 ) × 1.25 + 20% of 145 = ? – 40% of 65
(144 ÷ 4)² × (72 ÷ 12)³ = 12 ×? × (25920 ÷10)
22% of 400 + √ ? = 34% of 800 - 25% of 400
5/12 of 216 + 3/4 of 120 – 2/5 of 140 = ?
∛857375 + ∛91125 = ? + √6889
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?