Question
Find the value of the given trigonometric
expression: (sin 25°cos 65° + cos²25°) × sin 30° + (cos 60°tan 45°) × sec 60°Solution
(sin 25°cos 65° + cos²25°) × sin 30° + (cos 60°tan 45°) × sec 60° = {sin 25°cos (90° – 25°) + cos²25°} × sin 30° + cos 60°tan 45°sec 60° Using, cos (90° – A) = sin A = (sin²25° + cos²25°) sin 30° + cos 60°tan45°sec 60° Using, sin²A + cos²A = 1 = {1 × (1/2)} + {(1/2) × 1 × 2} = (1/2) + 1 = (3/2) Hence, option D.
LCM of two numbers is 56 times their HCF, with the sum of their HCF and LCM being 1710. If one of the two numbers is 240, then what is the other number?
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The sum of two numbers is 65 and their HCF is 13. Total number of such pairs of numbers is?  Â
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