Question
A tower is 60 meters high. From a point on the ground,
the angle of elevation of the top of the tower is 30°. Find the distance of the point from the base of the tower.Solution
Using the tan function: tan(30°) = height / distance. √3/3 = 60 / distance. Distance = 60 × 3 / √3 = 60√3 meters. Correct answer: a
If (cos A - sin A) = √2 cos (90° - A), then find the value of cot A.
sin10˚ x sin20˚ x sin40˚ =?
If (1+sinθ)/cosθ = x, then find the value of secθ?
1.
(1+sint)/(4-4sint)-(1-sint)/(4+4sint) =?
if 7 sin 2 x + 2 cos 2 x = 4 then find tan x
From a point 50 meters away from the base of a tower, the angle of elevation of the top of the tower is 30°. Find the height of the tower.
If x+ 1/x = 2cosθ, then the value of x³+ 1/x³ is
- If sin (a + b) = (√3/2) and cos (a – b) = (√3/2), then find sin a.
- If √3 cosec 2x = 2, then the value of x: