Question
If sin 28° = 15/17 , then tan 62° = ?
Solution
sin 28° = 15/17 = perpendicular/hypotenuse So perpendicular = 15 & hypotenuse = 17 so base = 8 But for angle 62° which is complimentary of 28°, perpendicular = 8 & base = 15. So tan 62° = perpendicular/base = 8/15 Alternate Method sin 28° = 15/17 or cos (90°-28°) = 15/17 or cos 62° = 15/17 -----(1) Squaring on both sides, we will get cos2 62° = 225/289 or (1 - sin2 62°) = 225/289 or sin2 62° = 1 - 225/289 = 64/289 = `(8/17)^2` So sin 62° = 8/17 ----(2) Hence tan 62° = sin62°/cos62° = `(8/17)/(15/17)` = `8/15` ` ` ` ` ` ` ` ` ` ` ` `
Answer the questions based on the information given below.
A & B means A is greater than B
A * B means A is not greater than B
A ...
Statements: M % N, N & A, A @ B, B # C
Conclusions: I. C & AÂ Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â Â II. M # B
...Statements: R > S > T ≥ U; Q ≥ R; W = V < U
Conclusions:
I. S > Q
II. W < T
III. Q > W
In the following question the relationship between different elements is given in the statements followed by three conclusions I, II and III. Read the...
In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is /are definitely true and ...
Statements:
N < P ≤ I = O; P ≥ J ≥ K ≥ W; Z ≤ M ≤ W
Conclusions:
I) O > Z
II) O = Z
...Statements: M $ K; K & N, N % R, R @ W
Conclusions:Â Â Â Â Â
I. W & KÂ Â Â Â Â Â Â Â
II. K & WÂ Â Â Â Â Â Â Â Â Â Â Â ...
Statements: I ≥ E = S > J < N > V > Q ≤ O
Conclusion
I: I > S
II: Q < N
In the question, assuming the given statements to be true, find which of the conclusion (s) among given two conclusions is /are definitely true and the...
Statements: F > V > W ≥ L > G; F ≤ O = M < I
Conclusions: I. M > LÂ Â Â II. V < I
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