Question
If cot x = (5/8), then find the value of
7cosxSolution
1 + cot2 x = cosec2 x Or, 1 + (5/8)2 = 1 + (25/64) = (89/64) = cosec2 x So, cosec x = (√89/8) Or, sin x = (8/√89) So, cos2 x = 1 - sin2 x So, cos2 x = 1 - (64/89) = (25/89) So, cos x = (5/√89) So, 7cos x = (35/√89)
612, 487,?, 396, 388, 387
Find the missing number in the given number series.
1, 2, 6, 24, 120, ?What will come in place of the question mark (?) in the following series?
36, 85, ?, 230, 330, 451
Find the missing term in the series:
2, 5, 11, 23, 47, ?
What will come in place of the question mark (?) in the following series?
400, 841, 1202, ?, 1716, 1885
44   45    41   50    ?      59    23
...221, 100, 0, -81, ?
...900 Â Â Â 90Â Â Â 18Â Â Â ? Â Â Â Â 2.16Â Â Â Â 1.08
16, 20, 11, 27, ?, 38
37, 57, 82, ?, 147, 187
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