Question
If cot x = (5/8), then find the value of
7cosxSolution
1 + cot2 x = cosec2 x Or, 1 + (5/8)2 = 1 + (25/64) = (89/64) = cosec2 x So, cosec x = (√89/8) Or, sin x = (8/√89) So, cos2 x = 1 - sin2 x So, cos2 x = 1 - (64/89) = (25/89) So, cos x = (5/√89) So, 7cos x = (35/√89)
What will come in the place of question mark (?) in the given expression?
(63 - ?) ÷ 5 + √625 = 19 X (9 - 6)
- What will come in place of (?), in the given expression.
(4² + 6²) × 2 = ? What will come in the place of question mark (?) in the given expression?
(40/25) X 80 - ? = 45% of 300 - 5525.6% of 250 + √? = 119
1220 ÷ 61 ÷ 5 + 450 of 20% - 70 = √ ?
Simplify the expression:
(5x + 15) / (x² + 3x)
What will come in the place of question mark (?) in the given expression?
435 ÷ 29 X 792 ÷ 44 = √(? + 14) + 35 + 221 ÷ 17
...192.251 + 326.233 + 125.021 + 19.273 = ?
36% of 640 – 12.5% of 352 + 25% of 640 = ? – 48% of 432
Simplify the following expressions and choose the correct option.
18 * 15 - {3/5 of 250 + 72}
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