Question
If SecA + TanA = 2√2 + 9, then find the value of
Sin A + Cos A.Solution
Sec²A – Tan²A = 1 (SecA – TanA) (SecA + TanA) = 1 (SecA – TanA) (2√2 + 9) = 1 (SecA - TanA) = 1/(2√2 + 9) SecA – TanA = 9 - 2√2 ………………(i) SecA + TanA = 9 + 2√2 ……………… (ii) By solving the two equations we get, 2SecA = 18 SecA = 9 CosA = 1/9 Sin²A + Cos²A = 1 Sin²A + 1/81 = 1 Sin²A = 1 - 1/81 Sin²A = 80/81 SinA= (4√5)/9 SinA + CosA = (4√5)/9+ 1/9 SinA + CosA = (1+4√5)/9
Presumption as to any electronic record 5 years old is made only if:
The Speaker of Lok Sabha may be removed
Concealment of design to facilitate waging of war is punishable_____
Conspiracy to wage war against the government in India, is punishable under?
According to the Bharatiya Nyaya Sanhita, 2023 what does petty organized crime mean?
When abetment of offence is done which is punishable with death or imprisonment for life, the offence is not committed then:
Offences commited beyond India_____.
All the members of an unlawful assembly when use force or violence in the prosecution of their common object, they are committing the offence of?
Maps or plans made by authority of government is proved to be true under s.___?
According to the IBC the liquidator shall communicate his decision of admission or rejection of claims to the creditor and corporate debtor within _____...
Relevant for Exams:
