Question
Solution
2sin2 380 sec2 520 + cos 640 sin 260 + sin2 640 / tan2 280 + cot2 230 – sec2 670 – cosec2 670 = 2 × 1 + cos2 640 + sin2 640 \ tan2 230 + cot2 230 = 2 + 1 / -(sec2 θ – tan2 θ) – (cosec2 θ – cot2 θ) = 3/-1-1 = -3/2 Sin A sec B = 1 If A + B = 900 Sec2 θ – tan2 θ = 1 cosec2 θ – cot2 θ = 1 Sin 2 θ + cos2 θ = 1
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