Question
Solution
2sin2  380 sec2  520 + cos 640 sin 260 + sin2 640 / tan2 280 + cot2  230 – sec2  670 – cosec2  670 = 2 × 1 + cos2  640 + sin2  640 \ tan2 230 + cot2  230 = 2 + 1 / -(sec2 θ – tan2  θ) – (cosec2  θ – cot2  θ) = 3/-1-1 = -3/2         Sin A sec B = 1 If A + B = 900 Sec2  θ – tan2  θ = 1 cosec2  θ – cot2  θ = 1 Sin 2 θ + cos2  θ = 1
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