Question
In triangle DEF, GH is drawn parallel to side EF. If DG = 9
cm, GE = 3 cm and DH = 6 cm, find DF.Solution
ATQ,
By Basic Proportionality Theorem,
(DG / GE) = (DH / HF)
=> (9 / 3) = (6 / HF)
=> HF = (6 × 3) / 9 = 2 cm
So, DF = DH + HF = 6 + 2 = 8 cm
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