Question
Given a right-angled triangle with the perpendicular
measuring 36 cm and the base measuring 48 cm, determine the length of the shortest median of the triangle.Solution
Using Pythagoras theorem, (Perpendicular)Â 2 Â + (Base)Â 2 Â = (Hypotenuse)Â 2 Or, 362 Â + 482 Â = (Hypotenuse)Â 2 Or, (Hypotenuse)2 Â = 1296 + 2304 = 3600 Since, the hypotenuse of a triangle cannot be negative. So, Hypotenuse = 60 cm Shortest median of a right-angle triangle = Circumradius = (Hypotenuse/2) = (60/2) = 30 cm
(22 + √3364)/(? + 4) = 10
28(4/5) + 52(1/2) × 8(2/7) - 11(1/5) = ? + 6(1/5)
(8.6 × 8.6 + 4.8 × 4.8 + 17.2 × 4.8) ÷ (8.62 – 4.82 ) = ? ÷ 19
The value of 42 ÷ 9 of 6 - [64 ÷  48 x 3 – 15 ÷ 8 x (11 – 17) ÷ 9] ÷ 14 is:
(21 × 51 + 81)/(9 × 14 - 30) = ?
 {(481 + 426) 2 - 4 × 481 × 426} = ?
- Find the simplified form of the following expression:
128 - 85 of 2 + 26 X 4 ?% of (168 ÷ 8 × 20) = 126
What will come in the place of question mark (?) in the given expression?
? = (27 × 13) – 26% of (412 – 92 )
82% of 400 + √(?) = 130% of 600 - 85% of 400
