Question
Given a right-angled triangle with the perpendicular
measuring 36 cm and the base measuring 48 cm, determine the length of the shortest median of the triangle.Solution
Using Pythagoras theorem, (Perpendicular) 2 + (Base) 2 = (Hypotenuse) 2 Or, 362 + 482 = (Hypotenuse) 2 Or, (Hypotenuse)2 = 1296 + 2304 = 3600 Since, the hypotenuse of a triangle cannot be negative. So, Hypotenuse = 60 cm Shortest median of a right-angle triangle = Circumradius = (Hypotenuse/2) = (60/2) = 30 cm
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B....
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