Question
Train A takes 90 seconds to cross a telegraph pole by
travelling at 18 kmph speed. Train B has its length 60% more than A. It takes 40 seconds to cross a pole. Find the time(in seconds) taken by train B to overtake train A.   ÂSolution
Let the length of A be x m. Given, ( x)/(18 × 5/18) = 90  ⇒ x = 450 Length of B = 450 + 60/100 × 450 = 450 + 270 = 720 m Speed of B = 720/40 = 18 m/s. ∴Required time = (450+720 )/(18-5) = 1170/13 = 90 seconds.
19.89% of 449.67 + 14.67% of 299.89 - 9.89% of 99.79 = ?
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
Find the approximate value of Question mark(?). There is no requirement to find the exact value.
? = 200.14 + 27.98 × 16.05 − (10.03)² - 12.9...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
1299.999 ÷ 325.018 × 24.996 = ?
What approximate value should replace the question mark?
99.95 − √529 × 3 + 1439.80 ÷ 12.02 = ?
619.97 ÷ 20.01 X 124.99 ÷ 24.91 = ?
124% of 620.99 + 11.65% of 1279.23 = ?
What approximate value should replace the question mark?
9.96% of 1200.10 − 25% of 4800 = ? − 7000.20
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